You are given an integer array nums consisting of n elements, and an integer k.
Find a contiguous subarray whose length is equal to k that has the maximum average value and return this value. Any answer with a calculation error less than 10-5 will be accepted.
Example 1:
Input: nums = [1,12,-5,-6,50,3], k = 4
Output: 12.75000
Explanation: Maximum average is (12 - 5 - 6 + 50) / 4 = 51 / 4 = 12.75
Example 2:
Input: nums = [5], k = 1
Output: 5.00000
Constraints:
- n == nums.length
- 1 <= k <= n <= 105
- -104 <= nums[i] <= 104
Explanation
val에 이전 Index의 값은 제거하고 다음 인덱스의 값을 넣어주며 k개의 arr의 값을 더한 뒤 k로 나누어 계산하며 저장해둔 값보다 큰 값이면 갱신해나가며 반복해서 해결
Time Complexity
O(N)
class Solution {
public double findMaxAverage(int[] nums, int k) {
double val = 0;
double max_val=0;
for(int i = 0;i<k;i++){
val += nums[i];
}
max_val=val/k;
for(int i = k;i<nums.length;i++){
val-=nums[i-k];
val+=nums[i];
if(val/k>max_val){
max_val=val/k;
}
}
return max_val;
}
}
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